Question

In the deep space between galaxies, where the density of atoms is as low as (1.00 X 10⁻6 atoms/m³) and the temperature is a frigid 2.7 K, what is the pressure?

a) (4.80 X 10⁻13 Pa)
b) (2.70 X 10⁻13 Pa)
c) (1.80 X 10⁻13 Pa)
d) (1.20 X 10⁻13 Pa)

Answer 1

The pressure in the deep space between galaxies with a density of 1.00 x 10^-6 atoms/m³ and a temperature of 2.7 K is approximately 2.70 x 10^-13 Pa.

Step-by-step explanation:

To find the pressure in the deep space between galaxies, we can use the ideal gas law, which states that pressure is equal to the product of the density, temperature, and the gas constant divided by the molar mass. In this case, the molar mass of atoms is very small, so we can assume a negligible value. Using the given density (1.00 x 10^-6 atoms/m³) and temperature (2.7 K), we can calculate the pressure.

Using the ideal gas law, the pressure is given by:

P = (nRT) / V

Where P is the pressure, n is the number of atoms per unit volume (density), R is the gas constant, T is the temperature, and V is the volume.

Since we want to find the pressure, we can rearrange the equation as:

P = (density x R x T)

Substituting the values, the pressure is approximately (2.70 x 10^-13 Pa).