Question

A projectile is launched at 37 degrees to the horizontal with a speed of 200 m/s from position A. How many seconds elapse after launch of the projectile before it returns to its original elevation at C?

Answer 1

24.5 s

Step-by-step explanation:

We can calculate time of flight of a projectile using below formula

T = (2Usinθ)/g

g = acceleration due to gravity= 9.81 m/s^2

U = initial velocity= 200 m/s,

θ = horizontal angle of projection= 37°

Sin(37°)= 0.60

If we input the values above, we have

=(2× 400×0.60)/9.81

= 480/9.81

T = 24.5 s

Hence, it takes 24.5 s before the projectile it returns to its original elevation at C