Question

Use the gravitational force equation to fill in the following table (G= 6.673 x 10-11 Nom²/kg2).

Mass of
Mass of
Object 2
Distance of
Separation*
Object 1
(kg)
(kg)
(m)
60.0
60.0
1.0
60.0
60.0
5.98x1024
11.96x1024
5.98x1024
5.98x1024
1.2x1022
1.901x1027
*The distance of separation means the distance between the centers of the two masses (NOT the
distance between the two objects' edges.)
Leo the cravitational accoloration aquation to fill in the following tabla (66.672 ~ 10-11 Nam2/21
60.0
60.0
60.0
60.0
6.37x106
6.37x106
3.18x106
6.47x106
Fgrav
(N)
1.15x106
6.98x107
Significance of Numbers
Two typical students in
physics class
A typical student on the
surface of the Earth
A typical student on an Earth
with twice the mass
A typical student on an Earth
with half the radius
A typical student in orbit 60
miles above the Earth
A typical student on the
surface of the Pluto
A typical student on the
"surface" of the Jupiter

Answer 1

The gravitational force between two 60.0 kg objects 1 m apart is calculated using Newton's law of gravitation F = G(M₁M₂)/R², yielding a force of 2.4 × 10⁻¹ N, which is an extremely small and imperceptible force in everyday experiences.

Step-by-step explanation:

When calculating the gravitational force between two objects, we use Newton's law of gravitation. The formula F = G(M₁M₂)/R² allows us to calculate the force (F) where G is the gravitational constant (6.67 × 10⁻¹¹ Nm²/kg²), M₁ and M₂ are the masses of the two objects, and R is the distance of separation between their centers.

For example, the gravitational force (F) between two students, each with a mass of 60.0 kg sitting 1.0 m apart, would be calculated as follows:

F = G(M₁M₂)/R² = (6.673 × 10⁻¹¹ Nm²/kg²) * (60 kg * 60 kg) / (1 m)² = 2.4 × 10⁻¹ N.

The force would be even smaller if the distance of separation is larger. Consequently, the gravitational force between two everyday objects like students is extremely minimal, making it imperceptible in daily experiences.