Question

The airplane returns to st louis by the same route. Because the prevailing winds push the airplane along, the return trip takes only 3.75 hours. What is the average speed for this trip answers 21-25

Answer 1

The average speed for the round trip is 9.7 miles per hour.

Step-by-step explanation:

To calculate the average speed for the return trip of the airplane, we need to know the total distance traveled and the time taken for the trip. As provided in the scenario, if the airplane travels the same route back to St. Louis and the distance each way is 40 miles, the total distance for the return trip would be 40 miles as well.

Since the distance is the same for the outbound and return trips, we can consider it as 80 miles.

The total time taken is the sum of the time for the outbound trip (4.5 hours) and the time for the return trip (3.75 hours), which is 8.25 hours.

To find the average speed, we divide the total distance by the total time: Average Speed = Total Distance / Total Time = 80 miles / 8.25 hours = 9.7 miles per hour.

Answer 2

`S = 678.71km/hr`

Step-by-step explanation:

The question has missing details. See comment for complete question

Given

`d = 2,742km` --- distance

`t_1 =4.33hr` --- time spent to Oregon

`t_2 =3.75` -- time spent back to St. Louis

Required

Calculate the average speed

First, we calculate the total distance of the trip.

Because it is a "to and fro" trip and the airplane passes the same route, the total distance D is:

`D = 2*d`

`D = 2*2742km`

`D = 5484km`

The total time taken (T) is:

`T = t_1 + t_2`

`T = 4.33hr + 3.75hr`

`T = 8.08hr`

The average speed (S) is then calculated as:

`S = (D)/(T)`

`S = (5484km)/(8.08hr)`

`S = 678.71km/hr`

The average speed for the trip is approximately 678.71