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PROBLEM SOLVING You are designing a marble basin

that will hold a fountain for a city park. The sides
and bottom of the basin should be 1 foot thick. Its
outer length should be twice its outer width and outer
height. What should the outer dimensions of the basin
be if it is to hold 36 cubic feet of water?
1 ft
2x
x
X

PROBLEM SOLVING You are designing a marble basin that will hold a fountain for a city-example-1

1 Answer

3 votes

To find the outer dimensions of the marble basin, solve the equation 4x^3 = 36. Taking the cube root of both sides, you find that the outer width is 3 feet, the outer length is 6 feet, and the outer height is 6 feet.

To find the outer dimensions of the marble basin, we need to use the formula for the volume of a rectangular prism, which is length x width x height.

In this case, the outer length is twice the outer width and outer height.

Let's assume that the outer width is x.

Therefore, the outer length would be 2x and the outer height would also be 2x.

So, the formula for the volume of the marble basin would be: 2x * x * 2x = 36 cubic feet.

Simplifying this equation, we get: 4x^3 = 36.

To solve this equation, we need to find the cube root of both sides.

Taking the cube root of 4x^3 gives us x = 3.

Therefore, the outer width would be 3 feet, the outer length would be 2 * 3 = 6 feet, and the outer height would also be 2 * 3 = 6 feet.

User Roberto Linares
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