Answer:
greater
Explanation:
the reason is because if you allow x to have a value that is less than 3,
![√(x - 3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v0f15j8zuzav1ccnab8ytbwn2wchwfqenb.png)
will produce a square root of a negative number, and the square root of a negative number requires the use of imaginary numbers, therefore limiting x to greater than or equal to 3 prevents this, also, consideration should be given to the fraction
![(3)/(x + 2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rtzjsfo8s7pl77ac2gr29w7werzwzc4dok.png)
if x has a value of -2 it causes the denominator of the fraction to be 0, the denominator should never be 0, by limiting x to greater than 3 to prevent the problem above you are already taking care of x not being able to be -2 since greater than 3 already excludes -2