Question

An astronaut travels to a far-away moon with a 1.5 m long pendulum. She finds it takes her pendulum 6.0837 seconds to complete one full oscillation.

Answer 1

The right response is "1.6 m/s²".

Step-by-step explanation:

The given values are:

Length of the pendulum,

= 1.5 m

Time period,

= 6.0837 seconds

As we know,

⇒
`T = 2\pi \sqrt{(L)/(g) }`

On substituting the given values, we get

⇒
`6.0837 = (2* 3.14) \sqrt{(1.5)/(g)`

⇒
`6.0837=6.28\sqrt{(1.5)/(g) }`

⇒
`g= 1.6 \ m/s^2`