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Find Q in the following equation:

Q±Q = (A±A)(B±B)/(C±C)
A) (A±A)(B±B)
B) (A±A)/(C±C)
C) (A±A)(B±B)(C±C)
D) (A±A)/(B±B)

User Jeffpkamp
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1 Answer

4 votes

Final answer:

The equation Q±Q = (A±A)(B±B)/(C±C) simplifies to 0 = 0, implying that the value of Q cannot be determined from this equation and is likely a result of a typo or incorrect transcription of the original problem.

Step-by-step explanation:

To find Q in the given equation Q±Q = (A±A)(B±B)/(C±C), we need to simplify it first. Since anything plus or minus itself is zero (A + A = 2A and A - A = 0), we can simplify both sides of the equation. On the left, Q±Q simplifies to 0, as any quantity plus or minus itself equals zero. The right side simplifies depending on the signs used. If it's addition, it becomes nonzero, but if it's subtraction, it also becomes zero like the left side.

However, since we are looking for Q, and the equation simplifies to 0, this means that the expression on the right side must also be zero for the equation to be valid, which only happens if it is in subtractive form. Therefore, in subtractive form we have 0 = 0. This implies that for any value of A, B, and C, their subtraction forms on the right will always result in zero, making the equation true.

However, the student's question possibly has a typo, because if it didn't, the answer would be simply that Q cannot be determined from the given information since it leads to 0=0.

User Chris Herring
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