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2 votes
Raul bikes 6 mi home from school

at a rate of 3 mi/h. Leah leaves
school 30 min after Raul and bikes
the same route at a rate of 4 mi/h.
How many hours does it take Leah
to catch up with Raul?

User Anas K
by
8.2k points

1 Answer

2 votes

Leah takes 1.5 hours to catch up with Raul.

Step-by-step explanation:

To determine how long it takes Leah to catch up with Raul, we can use the formula:

Distance = Rate × Time

Let's assume the time it takes Leah to catch up with Raul is 't' hours.

Raul bikes a distance of 6 miles at a rate of 3 miles per hour, so his time is:

Time = Distance / Rate = 6 miles / 3 miles per hour = 2 hours.

Leah starts biking 30 minutes (or half an hour) later than Raul. So when Leah starts, Raul has already been biking for 2 hours. Since Leah's rate is 4 miles per hour, her distance covered in 't' hours is:

Distance = Rate × Time = 4 miles per hour × t hours.

Since Raul and Leah cover the same distance, we can equate the distances:

2 hours × 3 miles per hour = 4 miles per hour × t hours.

Simplifying this equation gives us:

6 miles = 4t miles.

Dividing both sides of the equation by 4 gives:

t = 6 / 4 = 1.5 hours.

Therefore, it takes Leah 1.5 hours to catch up with Raul.

User Midstack
by
8.0k points