2 Answers

ReadyFreddy · Answer 1 · 2022-01-14T13:27:03+0000

Answer:

see below

Explanation:

I assume when you write x3 you mean

${x}^(3)$

so the expressions is:

$(6{x}^(3) - 5x) + (2 {x}^(3) + {x}^(2 ) + 10x)$

we can combine like terms

$6 {x}^(3) + 2 {x}^(3) + {x}^(2) - 5x + 10x$

$8 {x}^(3) + {x}^(2) + 5x$

the last thing we can do is factor out x because all 3 pieces have at least one x in them

$x( 8{x}^(2) + x + 5)$

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