This question is incomplete, the missing part is in the image below;
Answer:
the precise time that the cars started their trip is 12:00:00
Step-by-step explanation:
Given that;
from the image; The velocity of car1 V1 = 1/60 mile/seconds
Given the precise time that the car 1 passed the streetlight ( 12:25:00 )
if car 1 passed 25 seconds before car 2
meaning Car 2 passed the the streetlight at 12:50:00
now time delay is the difference between the two times; i.e
12:50:00 - 12:25:00 = 25 sec
so the distance between starting point and streetlight = 25×1 = 25 miles
Now, time required for Car1 to travel 25 miles distance will be;
t = distance/velocity of car1 = 25 / (
) = 1500 sec = 25 min
so the precise time that the cars started their trip will be;
12:25:00 - 25 min = 12:00:00
Therefore, the precise time that the cars started their trip is 12:00:00