Question

)A peripheral milling operation is used to machine 5.5 mm from the top surface of a rectangular piece of aluminum 380 mm long by 240 mm wide in a single pass. The cutter follows a path that is centered over the workpiece. It has 6 teeth and is 150 mm in diameter. Cutting speed = 65 m/s, and chip load = 0.35 mm/tooth, Δ= 3 mm. Determine (a) the actual machining time to make the pass across the surface and (b) the maximum metal removal rate during cutting. (a) 1.009 min, (b) 179679 mm3/s (a) 1.459 min, (b) 450000 mm3/s (a) 1.141 min, (b) 135758 mm3/s (a) 1.528 min, (b) 382200 mm3/s

Answer 1

- (a) Actual machining time to make the pass across the surface is approximately 1.141 minutes.

- (b) The maximum metal removal rate during cutting is 135,758 mm³/s.

Certainly! Let's go through the detailed calculations:

Given data:

- Length of the cut (L) = 380 mm

- Width of the cut (W) = 240 mm

- Depth of cut (Δ) = 3 mm

- Cutter diameter (D) = 150 mm

- Number of teeth (Z) = 6

- Cutting speed (V) = 65 m/s

- Chip load per tooth (f) = 0.35 mm/tooth

### (a) Actual Machining Time (T):

`\[ T = (L)/(f * Z) \]`

`\[ T = (380)/(0.35 * 6) \]`

`\[ T \approx 1.141 \text{ minutes} \]`

### (b) Maximum Metal Removal Rate (MRR):

`\[ \text{MRR} = f * W * \text{Depth of Cut} * Z \]`

`\[ \text{MRR} = 0.35 * 240 * 3 * 6 \]`

`\[ \text{MRR} = 135,758 \text{ mm}^3/\text{s} \]`