Question

Please help me with this question i don't understand it

Answer 1

The balanced equation and stoichiometry show that 6.69 grams of magnesium chloride (
`MgCl_2`) are produced when 5 grams of chlorine gas (
`Cl_2`) reacts with 10.3 grams of magnesium fluoride (
`MgF_2`).

Balanced chemical equation:

`Cl_2 + MgF_2 \rightarrow F_2 + MgCl_2`

Molar masses:

Molar mass of
`Cl_2`: 70.90 g/mol

Molar mass of
`MgF_2`: 63.31 g/mol

Molar mass of
`F_2`: 37.996 g/mol

Molar mass of
`MgCl_2`: 95.21 g/mol

Moles of each substance:

Moles of
`Cl_2`: 5 g / 70.90 g/mol = 0.0704 mol

Moles of
`MgF_2`: 10.3 g / 63.31 g/mol = 0.1626 mol

Moles of
`F_2` (to be synthesized): 4.1 g / 37.996 g/mol = 0.1080 mol

Using stoichiometry, we find that
`Cl_2` is the limiting reactant (1:1 ratio with
`MgF_2`).

The reaction consumes all 0.0704 mol of
`Cl_2`, producing 0.0704 mol of
`MgCl_2`.

Finally, convert moles of
`MgCl_2` to grams:

Mass of
`MgCl_2` = 0.0704 mol × 95.21 g/mol = 6.69 g

Therefore, the mass of magnesium chloride produced is 6.69 g.