Question

The stress in section AB is ______ Mpa. A) 22.5 B) 26.3 C) 28.8 D) 31.8 E) 44.2 F) 56.6 4. The stress in section BC is ______ Mpa.

A) 22.5

B) 26.3

C) 28.8

D) 31.8

E) 44.2

F) 56.6 5.


While under the load, the strain in section AB is ______x 10 -6 mm/mm.


A) 455

B) 808

C) 64,320

D) 125,300

E) 450,000

F) 722,300


6. While under the load, the strain in section BC is ______x 10 -6 mm/mm.


A) 455

B) 808

C) 64,320

D) 125,300

E) 45,000

F) 722,300


7. The total elongation of the bar while under the applied load is _____ mm.

A) 0.110

B) 0.322

C) 0.596

D) 12.5

E) 17.7

F) 18.3


8. Upon removal of the load, the permanent deformation of the bar is ______ mm.

A) 0.110

B) 0.322

C) 0.596

D) 12.5

E) 17.7

F) 18.3

Answer 1

The stress in section AB is 31.8 Mpa

The stress in section BC is 56.6 Mpa

Step-by-step explanation:

P.S - The exact question is -

As given,

`P_(A)` = 10 KN ,
`P_(B)` = 10 KN

d = 20 m for AB

d = 15 m for BC

Area of AB =
`(\pi )/(4) (d)^(2) = (\pi )/(4) (20)^(2) = (\pi )/(4) (400) = 100\pi`

Now,

Stress in AB =
`(P_(A) )/(Area) = (10 KN)/(100\pi ) = (10. 1000)/(100\pi ) = (100)/(\pi )` = 31.8 Mpa

Now,

Area in BC = =
`(\pi )/(4) (d)^(2) = (\pi )/(4) (15)^(2) = (\pi )/(4) (225) = 56.25\pi`

Now,

Stress in BC =
`(P_(B) )/(Area) = (10 KN)/(56.25\pi ) = (10. 1000)/(56.25\pi ) = (178.4)/(\pi )` = 56.6 Mpa