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Soil AWHC = 1.4 in/ft. Crop RZ = 5 ft. MAD = 45%. ETc 0.26 in/day. DU = 0.67. PI Losses = 9%. What is the Application Efficiency (%) with perfect timing?

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Final answer:

The calculation of Application Efficiency involves determining the effective water delivery to a crop considering various factors like AWHC, RZ, MAD, ETc, DU, and PI Losses, ensuring the calculation is done with perfect timing to avoid reductions due to losses.

Step-by-step explanation:

Calculating Application Efficiency

The question involves calculating the Application Efficiency for irrigation, taking into account various soil and crop parameters. The Application Efficiency is a measure of how effectively water is delivered to plants, considering the losses and the actual water utilized by the crops. Given that the Soil Available Water Holding Capacity (AWHC) is 1.4 inches per foot, the Crop Root Zone (RZ) is 5 feet, Management Allowed Depletion (MAD) is 45%, the Evapotranspiration rate of the crop (ETc) is 0.26 inches per day, Distribution Uniformity (DU) is 0.67, and Potential Irrigation Losses (PI Losses) are 9%. To calculate the Application Efficiency with perfect timing, we consider the amount of water needed to meet the crop's ETc requirements without over-irrigation. The efficiency is calculated without the reduction from PI Losses when timing is perfect.

In this scenario, the total volume of available water in the soil for the crop RZ would be the product of AWHC and RZ, adjusted for MAD. The daily water requirement is the ETc. To find out how much water needs to be applied, we have to account for the DU. After applying the necessary corrections due to losses and the efficiency of the system, we can determine the Application Efficiency.

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