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A pump delivers a gross flow rate of 2.4 CFS to a 12 acre field for 10 hours. The irrigation efficiency is 73%. What is the net amount of water benefiting the crop?

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Final answer:

The net amount of water benefiting the crop when a pump delivers a gross flow rate of 2.4 CFS to a 12 acre field for 10 hours with an irrigation efficiency of 73% is 63,072 cubic feet.

Step-by-step explanation:

You want to know the net amount of water benefiting the crop when a pump delivers a gross flow rate of 2.4 Cubic Feet per Second (CFS) to a 12 acre field for 10 hours, with an irrigation efficiency of 73%. First, let's calculate the total amount of water delivered:

Convert the flow rate to Cubic Feet per Hour (CFH): 2.4 CFS * 60 minutes * 60 seconds = 8,640 CFH.

Multiply by the total hours: 8,640 CFH * 10 hours = 86,400 cubic feet.

Now, let's calculate the net amount of water using the efficiency:

The net amount is 73% of the total delivered: 73% of 86,400 cubic feet = 0.73 * 86,400 cubic feet.

Calculate the net amount: 86,400 cubic feet * 0.73 = 63,072 cubic feet.

Therefore, the net amount of water benefiting the crop is 63,072 cubic feet.

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