Final answer:
To react with 1.36 mol of H3PO4, we need 2.04 mol of Ca(OH)2.
Step-by-step explanation:
To determine the number of moles of Ca(OH)2 required to react with 1.36 mol of H3PO4, we can use the stoichiometric coefficients from the balanced chemical equation: 3 Ca(OH)2 + 2 H3PO4 → Ca3(PO4)2 + 6H2O.
From the equation, we can see that the ratio of Ca(OH)2 to H3PO4 is 3:2. Therefore, to react with 1.36 mol of H3PO4, we need:
(1.36 mol H3PO4) x (3 mol Ca(OH)2 / 2 mol H3PO4) = 2.04 mol Ca(OH)2.