Final answer:
Crossing two heterozygous individuals (Bb x Bb) for bean color, where brown is dominant, results in a genotype ratio of 1 BB: 2 Bb: 1 bb and a phenotype ratio of 3 brown beans to 1 green bean.
Step-by-step explanation:
The question relates to Mendelian Genetics, specifically to determining the genotype and phenotype ratios when crossing two heterozygous individuals. For brown beans being dominant to green beans, we can assign the letter B to represent the dominant brown allele and b for the recessive green allele. When a heterozygous female (Bb) is crossed with a heterozygous male (Bb), the possible genotypes that can result from this cross are: BB, Bb, Bb, and bb. To determine the genotype and phenotype ratios, we can use a Punnett square, which visualizes the crosses between the parental genotypes. The resultant genotype ratio is 1 BB: 2 Bb: 1 bb, which corresponds to a phenotype ratio of 3 brown beans to 1 green bean.