This question is incomplete, the complete question is;
Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3feet [ft] so the total pressure at the bottom of the container will not exceed 26 pound-force per square inch [psi]. Assume the height of the tank is sufficient to store the amount of olive oil required, and the surface pressure is 1 atmosphere [atm]. The specific gravity of olive oil is 0.86.
Answer:
A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo
Step-by-step explanation:
Given the data in the question;
Using SI units
Diameter = 3 ft = 3 × 0.3048 = 0.9144 m
pressure at bottom Pb = 26 psi = 26 × 6.89476 × 1000 = 179263.76 pascal
surface pressure Ps = 1 atm = 1 × 101325 = 101325 pascal
specific gravity = 0.86
we know that; density of water = 1000 kg/m³
so, density of oil P = density of water × specific gravity
= 1000 × 0.86 = 860 kg/m³
pressure at depth can be related to pressure at surface;
Pb = Ps + Pgh
acc. due gravity g = 9.81 m/s²
we substitute
179263.76 = 101325 + ( 860 × 9.81 × h)
8436.6h = 179263.76 - 101325
8436.6h = 77938.76
h = 77938.76 / 8436.6
h = 9.238 m
Now;
Volume of the cylinder = π/4 × D² × h
we substitute
Volume of the cylinder = π/4 × ( 0.9144 )² × 9.238
Volume of the cylinder = 6.0665 m³
we know that; 1 m³ = 264.172 gal
so; Volume of the cylinder = 6.0665 × 264.172 gal
Volume of the cylinder = 1602.6 gallons
Therefore, A maximum of 1602.6 gallons of olive oil can be stored in the closed cylindrical silo