435,352 views
39 votes
39 votes
I need help! could someone help me with this? is from Imagine Math

I need help! could someone help me with this? is from Imagine Math-example-1
User Trevor Hickey
by
2.5k points

1 Answer

13 votes
13 votes

Answer:

1st: One solution

2nd: Infinite many solutions

3rd: No solution

4th: No Solution

5th: One Solution

Explanation:

1st:

The solution is (6,9)

x = 6 if a vertical line going though (6,0)

y = 9 is a horizontal line going through (0,9)

The two lines with intersect at (6,9)

2nd:

3y = 15x + 6 If you divide all the way through by 3, you get

y = 5x + 2

This is identical to the first equation given. Since it is the same line, the answer is infinite many solutions.

3rd:

3y = x + 2 Divide all the way through by 3

y = 1/3 x + 2/3

9y = 3x + 7 Divide all the way through by 9

y = 1/3 x + 7/9

Since the slopes are the same in both equations (1/3), these line are parallel and will never intersect.

4th:

Since the slopes are both the same (2), the lines are parallel and they will never intersect, so the answer is no solution.

5th:

2y = 3x Divide both sides by 2

y = 3/2

-5y = -10 Divide both sides by -5

y = 2x

These equations are proportional so they go through the origin. They both have a y intercept of zero, so they intersect at (0,0). The answer is one solution.

User Jaymee
by
2.8k points