Question

The licensed practical nurse is collaborating with the registered nurse validating a test dose of mannitol solution IV for a client with marked oliguria. The ordered test dose is 0.2 g/kg of 15% mannitol solution IV. The client weighs 132 lb (59.8 kg). How many grams should the nurse administer? Record your answer as a whole number.

Answer 1

The nurse should administer 12 grams of the mannitol solution IV as the test dose for a client weighing 59.8 kg.

Step-by-step explanation:

The licensed practical nurse needs to calculate the amount of a test dose of mannitol solution IV to administer to a client. The dose required is 0.2 g/kg, and the client weighs 132 lb, which is approximately 59.8 kg. To find the correct dose in grams, the nurse should multiply the client's weight in kilograms by the dosage per kilogram.

The calculation would be:

59.8 kg x 0.2 g/kg = 11.96 g

Since the question asks for the answer as a whole number, the nurse should administer 12 grams of the mannitol solution.