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A 5kg rock is resting on the moon. The moon has a mass of 2.2x1023 kg. If the moon has a radius

of 30,000m, determine the force of gravitation between the rock and the moon. (Round to the
nearest HUNDREDTHS place)

User Alice Chan
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1 Answer

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The gravitational force between the 5 kg rock and the moon is approximately 2.04 × 10^4 N.

To determine the force of gravitation between the rock and the moon, you can use Newton's law of gravitation, which is given by the formula:

F = G × m1 × m2 / r^2

where:

F is the force of gravitation,

G is the gravitational constant (6.67430 × 10^-11 Nm^2/kg^2),

m1 and m2 are the masses of the two objects,

r is the separation between the centers of the two masses.

In this case:

m1 is the mass of the rock (5 kg),

m2 is the mass of the moon (2.2 × 10^23 kg),

r is the distance between the center of the rock and the center of the moon (30,000 m + radius of the moon).

Let's calculate it:

r = 30,000 m + 30,000 m = 60,000 m

F = (6.67430 × 10^-11 Nm^2/kg^2 × 5 kg × 2.2 × 10^23 kg) / (60,000 m)^2

Now, plug in the values and calculate:

F ≈ (6.67430 × 10^-11 × 5 × 2.2 × 10^23) / (60,000)^2

F ≈ (7.34175 × 10^13) / (3.6 × 10^9)

F ≈ 2.03882 × 10^4 N

Therefore, the force of gravitation between the rock and the moon is approximately 2.04 × 10^4 N (rounded to the nearest hundredths).

User Bamdad
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