Answer:
A
Explanation:
by using the eqn to find for a straight line
slope = ∆y/∆x
(1,4) and (0,0) since both points are in the line
slope = 4
then,
y-y'=slope(x-x')
y-4=4(x-1)
y-4=4x-4
y=4x-4+4
y=4x
but the graph is parabolic thus
y=4x^2
this is how I did it I have no idea to do anything else so hope it works