In triangle ABC, AC = 15.83 cm. In triangle PQR, PR = 16.97 cm. In triangle MNO, MO = 16 cm.
In triangle ABC, with angle ABC = 90 degrees and angle BAC = 50 degrees, AB = 10 cm and AC = x.
To find the value of x, we can use the trigonometric function cosine. Since the cosine of an angle is equal to the adjacent side divided by the hypotenuse, we have cos(50 degrees) = AB/AC.
Rearranging the equation, we get AC = AB/cos(50 degrees).
Plugging in the values, AC = 10 cm / cos(50 degrees) = 15.83 cm.
In triangle PQR, with angle PQR = 90 degrees and angle QRP = 45 degrees, PQ = 12 cm and PR = x.
To find the value of x, we can again use the cosine function.
This time, we need to use the angle QRP, so cos(45 degrees) = PQ/PR.
Rearranging the equation, we get PR = PQ/cos(45 degrees).
Plugging in the values, PR = 12 cm / cos(45 degrees) = 16.97 cm.
In triangle MNO, with angle MNO = 90 degrees and angle NOM = 60 degrees, MN = 8 cm and MO = x.
To find the value of x, we can use the cosine function.
This time, we need to use the angle NOM, so cos(60 degrees) = MN/MO.
Rearranging the equation, we get MO = MN/cos(60 degrees).
Plugging in the values, MO = 8 cm / cos(60 degrees) = 16 cm.
The probable question may be:
Find the value of x for each question
1. In triangle ABC , angle ABC= 90 degree, angle BAC=50 degree AB= 10cm , AC=x.
2. In triangle PQR , angle PQR= 90 degree, angle QRP=45 degree, PQ= 12cm , PR=x.
3. In triangle MNO , angle MNO= 90 degree, angle NOM=60 degree, MN= 8cm , MO=x.