Question

Write an expression for the equilibrium constant for the following reversible reaction N2+3H 2NH3

Answer 1

The equilibrium constant (K) expression for the reversible reaction
`\(N_2 + 3H_2 \rightleftharpoons 2NH_3\)` is given by
`\(([NH_3]^2)/([N_2][H_2]^3)\)`. It represents the ratio of product to reactant concentrations, each raised to their respective coefficients, providing insight into the equilibrium position.

For the reversible reaction
`\(N_2 + 3H_2 \rightleftharpoons 2NH_3\)`, the equilibrium constant (K) expression is given by the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of their respective coefficients in the balanced chemical equation:

`\[ K = ([NH_3]^2)/([N_2][H_2]^3) \]`

Here:

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`\([NH_3]\)` is the concentration of ammonia,

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`\([N_2]\)` is the concentration of nitrogen gas,

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`\([H_2]\)` is the concentration of hydrogen gas.

Note: Square brackets denote molar concentrations. The equilibrium constant expression is based on the law of mass action and helps describe the position of the equilibrium for a given reaction.