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Solve the right triangle.

3-√3
I
30⁰
H
Write your answers in simplified, rationalized form. Do not round.
D =
H] =
m2] =

Solve the right triangle. 3-√3 I 30⁰ H Write your answers in simplified, rationalized-example-1
User Arthi
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2 Answers

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M=20 h=3 essa é a resposta
User Jeremy Gruenwald
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To solve the right triangle, we are given the following information:

Side a = 3-√3

Side b = 1

Angle A = 30°

We can use the trigonometric ratios sine, cosine, and tangent to find the missing sides and angles of the triangle.

1. Find angle B:

Since angle A is 30°, angle B is 90° (as it is a right triangle). Therefore, angle C = 180° - angle A - angle B = 180° - 30° - 90° = 60°.

2. Find side c:

We can use the sine ratio to find side c:

sin(A) = opposite/hypotenuse

sin(30°) = a/c

c = a/sin(30°) = (3-√3) / sin(30°)

3. Simplify side c:

To simplify side c, we need to rationalize the denominator.

We know that sin(30°) = 1/2, so c = (3-√3) / (1/2) = 2(3-√3) = 6-2√3

4. Find side d:

We can use the cosine ratio to find side d:

cos(A) = adjacent/hypotenuse

cos(30°) = b/d

d = b/cos(30°) = 1 / cos(30°)

5. Simplify side d:

To simplify side d, we need to rationalize the denominator.

We know that cos(30°) = √3/2, so d = 1 / (√3/2) = 2/√3 = (2√3) / 3

Therefore, the lengths of the sides of the right triangle are:

a = 3-√3

b = 1

c = 6-2√3

d = (2√3) / 3

User Wch
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