Final answer:
The bus traveled an average velocity of 5 m/s in 5 seconds. The bus traveled a distance of 800 meters when the velocity reached 40 m/s.
Step-by-step explanation:
To find the average velocity of the bus in 5 seconds, we need to first find the final velocity of the bus after 5 seconds. Since the bus has a constant acceleration of 2 m/s², we can use the equation:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given that the initial velocity is 0 m/s, the acceleration is 2 m/s², and the time is 5 seconds, we can substitute these values into the equation:
v = 0 + (2)(5) = 10 m/s
Therefore, the final velocity of the bus after 5 seconds is 10 m/s.
The average velocity can be calculated using the formula:
Average velocity = (initial velocity + final velocity) / 2
Since the initial velocity is 0 m/s, the final velocity is 10 m/s, we can substitute these values into the formula:
Average velocity = (0 + 10) / 2 = 5 m/s
So, the bus has traveled an average velocity of 5 m/s in 5 seconds.
To find the distance traveled by the bus when the velocity has reached 40 m/s, we can use the equation:
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
Given that the initial velocity is 0 m/s, the acceleration is 2 m/s², and the final velocity is 40 m/s, we can substitute these values into the equation:
s = (v² - u²) / (2a) = (40² - 0²) / (2 * 2) = 800 m
Therefore, the bus has traveled a distance of 800 meters when the velocity has reached 40 m/s.