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(3) In a lifting mechanism, the effort P kg is partly constant and partly varies as the load W tonnes. If P=2.32, when W-2 and P= 3.19 when W-5. (a) find the equation connecting P and W (b) find P when W=12​

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Answer:

(a) To find the equation connecting P and W, we can set up a system of equations using the given information.

Given: P = 2.32 when W = 2

and P = 3.19 when W = 5

Let's assume that the constant part of the effort is represented by K, and the varying part of the effort is represented by M.

So, the equation relating P and W can be written as:

P = K + M * W

Substituting the given values, we get:

2.32 = K + M * 2

3.19 = K + M * 5

Solving these two equations simultaneously will give us the values of K and M.

Subtracting the first equation from the second equation, we get:

3.19 - 2.32 = K + M * 5 - (K + M * 2)

0.87 = 3M

Dividing both sides by 3, we get:

M = 0.29

Substituting the value of M in the first equation, we can solve for K:

2.32 = K + 0.29 * 2

2.32 = K + 0.58

K = 2.32 - 0.58

K = 1.74

Therefore, the equation connecting P and W is:

P = 1.74 + 0.29 * W

(b) To find P when W = 12, we can substitute W = 12 into the equation we found in part (a):

P = 1.74 + 0.29 * 12

P = 1.74 + 3.48

P = 5.22

Therefore, when W = 12, P = 5.22 kg.

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