Question

A customer bought six cups of coffee and four bagels and paid $10. Another customer bought three cups of coffee and two bagels and paid $15. How much are each cup of coffee and each bagel?

Answer 1

The cost per cup of coffee is $1, and the cost per bagel is $2.

Let's denote the cost of each cup of coffee as C and the cost of each bagel as B.

The total cost for the first customer, who bought six cups of coffee and four bagels and paid $10, is given by the equation 6C + 4B = 10

The second customer, buying three cups of coffee and two bagels and paying $15, incurs a total cost of 3C + 2B = 15

Solving this system of linear equations simultaneously, we find that C = 1 and B = 2

Therefore, each cup of coffee costs $1, and each bagel costs $2.

This solution satisfies both customers' transactions, as substituting C = 1 and B = 2 into both equations yields $10 for the first customer and $15 for the second customer.

Hence, the cost per cup of coffee is $1, and the cost per bagel is $2.