Question

According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible)

a. Compute the probability that a randomly selected peanut M&M is not brown.

Answer 1

The probability that a randomly selected peanut M&M is not brown is 0.8800.

Step-by-step explanation:

To compute the probability that a randomly selected peanut M&M is not brown, you can subtract the probability of selecting a brown M&M from 1, as this will give you the total probability of selecting M&Ms of any other color. Given that the probability of selecting a brown M&M is 12%, or 0.12, the calculation would look as follows:

P(not brown) = 1 - P(brown)

P(not brown) = 1 - 0.12

P(not brown) = 0.88

Therefore, the probability that a randomly selected peanut M&M is not brown is 0.8800 (rounded to four decimal places).