Question

Two pipes Can fill tank in 6 hours the larger pipe works twice as fast as the smaller tank, haw lang would it take casn pipe to fill the tank if they worked separctly​

Answer 1

Using algebra, it is determined that the smaller pipe can fill the tank in 18 hours while the larger pipe, being twice as fast, can fill it in 9 hours.

Step-by-step explanation:

The question asks about two pipes filling a tank, with one being twice as fast as the other. It is mentioned that together they can fill the tank in 6 hours. To find out how long each pipe would take to fill the tank separately, we first need to establish a rate for each pipe. Let's denote the smaller pipe's filling rate as 1/x tanks per hour. Therefore, the larger pipe, being twice as fast, has a filling rate of 1/(x/2) or 2/x tanks per hour. Combining their filling rates, we get 1/x + 2/x = 3/x, which fills the tank in 6 hours.

Thus, 3/x = 1/6, and solving for x gives us x = 18. This means the smaller pipe fills the tank in 18 hours. Consequently, the larger pipe, being twice as fast, would fill the tank in 18/2 = 9 hours.