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How many total atoms are in the formula 3Sr(MnO4)2

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answer!!!

so basically:

To determine the total number of atoms in the formula 3Sr(MnO4)2, we need to break down the formula and count the number of atoms for each element.

The formula 3Sr(MnO4)2 consists of three components: 3 Sr atoms, 2 MnO4 groups, and a total of 8 oxygen atoms within those MnO4 groups.

Breaking it down further:

1. Sr: The coefficient "3" indicates that there are 3 Sr atoms.

2. MnO4: The coefficient "2" indicates that there are 2 MnO4 groups. Within each MnO4 group, there is 1 Mn atom and 4 O atoms.

Mn: There are 2 MnO4 groups, so we have a total of 2 Mn atoms.

O: Each MnO4 group has 4 O atoms, and there are 2 MnO4 groups. Therefore, there are 4 x 2 = 8 O atoms.

To calculate the total number of atoms, we sum up the number of atoms for each element:

Total atoms = Number of Sr atoms + Number of Mn atoms + Number of O atoms

Total atoms = 3 + 2 + 8

Total atoms = 13

Therefore, the formula 3Sr(MnO4)2 contains a total of 13 atoms

User Shehan Ekanayake
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