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Can you help me solve it.​

Can you help me solve it.​-example-1
User Neshat
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The fractions for both the first and second draws (A and B) from the bag are the same, with the probability of drawing a green marble being 7/11 and the probability of drawing a purple marble being 4/11.

To solve this problem, we must calculate the probabilities of drawing green and purple marbles from a bag that contains 7 green marbles and 4 purple marbles, given that we are replacing the marbles after each draw.

For the first marble (A), the probability of drawing a green marble is 7/11 since there are 7 green marbles out of a total of 11. Similarly, the probability of drawing a purple marble is 4/11 as there are 4 purple marbles out of 11.

Since the marble is replaced after the draw, the probabilities remain the same for the second marble (B). Therefore, the probability of drawing a green marble again is 7/11, and the probability of drawing a purple marble remains 4/11.

So, the fractions that should go in the boxes marked A and B are:

First marble (A): Green - 7/11, Purple - 4/11

Second marble (B): Green - 7/11, Purple - 4/11

These are the simplest forms of the fractions representing the probabilities of drawing each color marble from the bag at each draw.

User Vivin
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