According to Wien's Law, as the temperature of an object increases, the peak wavelength of its emitted blackbody radiation decreases. This signifies a shift towards shorter, more energetic wavelengths, supporting the increases. Here option D is correct.
This phenomenon is described by Wien's Law, which states that the wavelength of the peak intensity of blackbody radiation is inversely proportional to the temperature of the object.
Mathematically, it is expressed as λ_max = b / T, where λ_max is the peak wavelength, b is Wien's displacement constant, and T is the temperature in kelvins.
As the temperature of the object increases, the value of T in the denominator increases, leading to a decrease in the wavelength of the peak intensity. This implies that at higher temperatures, the object emits shorter-wavelength, more energetic radiation.
Conversely, at lower temperatures, the peak wavelength is longer, corresponding to less energetic radiation. Here option D is correct.
Complete question:
Assume an object is emitting blackbody radiation. A body in a room at 300 K is heated to 3,000 K. The wavelength of the most intense EM radiation emitted by the body at 3,000 K is the wavelength of the most intense EM radiation at 300 K. As the temperature of an object increases, the wavelength of the brightest light emitted
A - doesn't change.
B - decreases
C - depends on the size of the body.
D - increases.
E - depends on the composition of the body.