Final answer:
The genotype of each parent goat is PpWw, and by performing a Punnett square cross, the phenotypic ratios of the F1 generation are approximately 9:3:3:1 for the traits pulled horns and wattles.
Step-by-step explanation:
Given that some offspring resulted with horns and no wattles, we can infer that both parents are heterozygous for both traits.
Therefore, the genotype of each parent would be PpWw.
To find the phenotypic ratios of the F1 generation, we use a Punnett square which predicts the outcomes of genetic crosses.
When we cross the genotypes PpWw × PpWw, the Punnett square shows a ratio of 9:3:3:1.
This means in a group of 16 offspring, approximately 9 will have both pulled horns and wattles (PW), 3 will have pulled horns without wattles (Pw), 3 will have horns but have wattles (pW), and 1 will have horns and no wattles (pw).