Question

An athlete whirls a 12 kg rock tied to the end of a 10 m chain in a horizontal circle. The hammer travels with a constant speed of 4 m/s. What is the centripetal force on the hammer? (Round to the nearest tenths) Responses 120 N 120 N 19.2 N 19.2 N 14.4 N 14.4 N 25.6 N

Answer 1

answer!!!!

so basically:


The centripetal force on the hammer can be calculated using the formula!!!

F = (m * v^2) / r

Where:

- F is the centripetal force

- m is the mass of the hammer (12 kg)

- v is the velocity of the hammer (4 m/s)

- r is the radius of the circular motion (10 m)

Substituting the given values into the formula:

F = (12 kg * (4 m/s)^2) / 10 m

Calculating the values within the parentheses:

F = (12 kg * 16 m^2/s^2) / 10 m

F = 192 kg*m/s^2 / 10 m

Simplifying:

F = 19.2 N

Therefore, the centripetal force on the hammer is approximately 19.2 Newtons (N).

hope it helps!! ily!! - aydn