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Triangle SKY with vertices S(-6,-5),K(-1,-2),and Y(-4,-7),(0,7)

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The lengths of the sides of triangle SKY are: SK = KY = √34 and SY = 2√2.

The vertices of the triangle SKY are S(-6,-5), K(-1,-2), and Y(-4,-7). To find the length of each side of the triangle, we can use the distance formula.

The distance formula is given by:

d = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates, we get:

d(SK) = √((-1 - (-6))^2 + (-2 - (-5))^2) = √((5)^2 + (3)^2) = √34

d(KY) = √((-4 - (-1))^2 + (-7 - (-2))^2) = √((3)^2 + (-5)^2) = √34

d(SY) = √((-4 - (-6))^2 + (-7 - (-5))^2) = √((-2)^2 + (-2)^2) = 2√2

Therefore, the lengths of the sides of triangle SKY are: SK = KY = √34 and SY = 2√2.

The probable question may be:

Triangle SKY with vertices S(-6,-5),K(-1,-2),and Y(-4,-7),(0,7). What are the lengths of the sides of triangle SKY?

User Johan Lindkvist
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