To find the IR drop in R₁, we note that the full current I flows through R₁. Thus its IR drop is V₁ = IR₁. The total current I is found using Ohm's law for the circuit. The value of I can then be used to calculate V₁.
To find the IR drop in R₁, we note that the full current I flows through R₁. Thus its IR drop is V₁ = IR₁. We must find I before we can calculate V₁. The total current I is found using Ohm's law for the circuit. That is, V_total = I * R_total.
From the given values, V = 66.959 V and R_total = R₁ + R₂ = 680 Ohms + 560 Ohms = 1240 Ohms. Plugging in these values, we can solve for I: I = V_total / R_total = 66.959 V / 1240 Ohms = 0.0538 A. Now we can calculate V₁ using Ohm's law for R₁: V₁ = I * R₁ = 0.0538 A * 680 Ohms = 36.5 V.