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MathMathMathMathMathMathMath-example-1
User Jonovos
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Answer:

I hated deltamath (I think it is, looks familiar), anyways I believe the measure of angle SQR is 66.8 degrees

Explanation:

m/RST = (6x + 7)°

m/QRS = (x-3)°

m/SQR = (3x + 20)°

According to triangle angle sum property, we have

m/RST + m/QRS + m/SQR = 180

Now we can substitute the given angle measures

(6x + 7) + (x-3) + (3x + 20) = 180

10x + 24 = 180

10x = 156

x = 15.6

Now we can find the measure of angle SQR

m/SQR = (3x + 20)°

m/SQR = 3(15.6) + 20

m/SQR = 46.8 + 20

m/SQR = 66.8°

User Nathan Manousos
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