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An object is launched at a velocity of 158 m/s at an angle of 46 degrees.

What are the initial horizontal and vertical components of that velocity?

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Final answer:

The initial horizontal and vertical components of an object launched at 158 m/s at a 46-degree angle are approximately 109.64 m/s and 113.62 m/s, respectively.

Step-by-step explanation:

The question asks for the initial horizontal and vertical components of the velocity of an object launched at a velocity of 158 m/s at an angle of 46 degrees.

To find these components, we use trigonometric functions:

  • The initial horizontal component (vx) can be calculated using the cosine function: vx = v * cos(θ)
  • The initial vertical component (vy) can be calculated using the sine function: vy = v * sin(θ)

Plugging in the given values:

  • vx = 158 m/s * cos(46°) = 158 m/s * 0.694 = 109.64 m/s
  • vy = 158 m/s * sin(46°) = 158 m/s * 0.719 = 113.62 m/s

Therefore, the initial horizontal component of the velocity is approximately 109.64 m/s, and the initial vertical component is approximately 113.62 m/s.

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