Question

The equation of a circle on the coordinate plane is (x-3)^2+(x+2)^2= 16. What is the diameter of the circle?

Answer 1

Answer: 8

Step-by-step explanation

The standard circle template is

(x-h)^2 + (y-k)^2 = r^2

where,

• (h,k) = center
• r = radius

Compare the 16 to r^2 to find that r^2 = 16 solves to r = 4.

The radius of 4 then doubles to the diameter of 8