Question

A line contains the point (-3,2) and (4,-4) what is the slope

Answer 1

Answer: -6/7 or -0.87

Explanation:

slope (m) = rise/run = (y2 - y1)/(x2-x1)

in the problem your values are: x1 = -3, x2 = 4, y1 = 2, y2 = -4)

substitute the values;

`m = (-4-2)/(4-(-3)) = (-6)/(7)` or -0.87
note: if m is negative the line is inclined downwards to the right.

Answer 2

slope m = -
`(6)/(7)`

Explanation:

calculate the slope m, using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

let (x₁, y₁ ) = (- 3, 2 ) and (x₂, y₂ ) = (4, - 4 )

substitute these values into the formula for m

m =
`(-4-2)/(4-(-3))` =
`(-6)/(4+3)` = -
`(6)/(7)`