Question

Construction workers are using a crane to lift a circular platform. The radius of the platform is 10 meters. A 2 meter tall worker is directly under the center of the platform as it is lifted. When the platform is 24 meters above the ground, the cable snaps and the platform starts to fall. It takes 0.75 seconds for the worker to notice the platform is falling. What is the minimum acceleration the worker mush have to get out of the way of the platform?

Answer 1

The minimum acceleration the worker must have to get out of the way of the falling platform is 64 m/s^2.

Step-by-step explanation:

To calculate the minimum acceleration the worker must have to get out of the way of the falling platform, we can analyze the situation.

The time it takes for the worker to notice the falling platform is 0.75 seconds.

During this time, the platform falls a distance of 24 meters.

We can use the equation d = 0.5 * a * t^2, where d is the distance, a is the acceleration, and t is the time, to solve for the minimum acceleration.

Plugging in the values, we get 24 = 0.5 * a * (0.75)^2.

Solving for a, we find that the minimum acceleration the worker must have is 64 m/s^2.