Question

Mathematics pa help po

Answer 1

1.
`5√(2) \)`

2.
`9√(x) \)`

3.
`5m√(3n) \)`

4.
`6x^2y^3√(2y) \)`

5.
`(√(2))/(5) \)`

6.
`(2√(3))/(5) \)`

7.
`(3y^2√(5x))/(16x) \)`

8.
`11x^3y√(z) \)`

9.
`8x√(2x) \)`

10.
`(3x√(x))/(4y^2) \)`

How did we get the values?

Let's simplify each expression:

1.
`\( √(50) \)`

`- \( √(50) = √(25 * 2) \\= √(25) * √(2) \\= 5√(2) \)`

2.
`\( √(81x) \)`

-
`\( √(81x) = √(9 * 9 * x) \\= 9√(x) \)`

3.
`\( √(75m^2n) \)`

`- \( √(75m^2n) = √(25 * 3 * m^2 * n) \\= 5m√(3n) \)`

4.
`\( 3√(8x^4y^7) \)`

`- \( 3√(8x^4y^7) = 3 * 2x^2y^3 √(2y) \\= 6x^2y^3√(2y) \)`

5.
`\( (√(2))/(√(25)) \)`

`- \( (√(2))/(√(25)) = (√(2))/(5) \)`

6.
`\( \sqrt{(12)/(25)} \)`

`- \( \sqrt{(12)/(25)} = (√(12))/(√(25)) \\= (2√(3))/(5) \)`

7.
`\( (√(45x^3y^4))/(16x^2) \)`

`- \( (√(45x^3y^4))/(16x^2) = (3xy^2√(5x))/(16x^2) \\= (3y^2√(5x))/(16x) \)`

8.
`\( √(121x^6y^3z) \)`

`- \( √(121x^6y^3z) = √(11^2 * x^6 * y^3 * z) \\ = 11x^3y√(z) \)`

9.
`\( (√(128x^3y^5))/(√(2xy^2)) \)`

`- \( (√(128x^3y^5))/(√(2xy^2)) = (8xy^2√(2x))/(√(2xy^2)) \\= 8x√(2x) \)`

10.
`\( \sqrt{(0.09x^3)/(0.16y^4)} \)`

`- \( \sqrt{(0.09x^3)/(0.16y^4)} = (√(0.09x^3))/(√(0.16y^4)) \\= (0.3x√(x))/(0.4y^2) \\= (3x√(x))/(4y^2) \)`