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How many molecules are there in 26 g cisplatin, Pt(NH₃)₂Cl₂, an anti-cancer agent used in the treatment of solid tumors?

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Final answer:

To determine the number of molecules in 26 g of cisplatin, we use Avogadro's number and the molar mass of cisplatin. The molar mass of cisplatin is calculated by summing the atomic masses of all the elements in the compound. We can then use Avogadro's number to convert grams to molecules.

Step-by-step explanation:

To determine the number of molecules in 26 g of cisplatin, we need to use the concept of Avogadro's number and molar mass. First, find the molar mass of cisplatin by summing up the atomic masses of all the elements in the compound:

Molar mass of Pt: 195.08 g/mol

Molar mass of N: 14.01 g/mol

Molar mass of H: 1.01 g/mol

Molar mass of Cl: 35.45 g/mol

Number of atoms of each element in cisplatin:

Number of Pt atoms = 1

Number of N atoms = 2

Number of H atoms = 6

Number of Cl atoms = 2

Adding up the molar masses gives:

Total molar mass of cisplatin = (1 × 195.08) + (2 × 14.01) + (6 × 1.01) + (2 × 35.45) = 300.02 g/mol

Now, use Avogadro's number (6.022 × 10^23) to convert from grams to molecules:

Number of molecules = (26 g / 300.02 g/mol) × (6.022 × 10^23 molecules/mol) = 5.19 × 10^22 molecules

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