Final answer:
The product of reductive ozonolysis of 1,2-dimethylcyclohexene consists of two ketones: acetone and a cyclic ketone, resulting from the cleavage of the double bond and subsequent reduction.
Step-by-step explanation:
Reductive Ozonolysis of 1,2-Dimethylcyclohexene
The structure of the product from the reductive ozonolysis of 1,2-dimethylcyclohexene involves breaking the double bond and forming two carbonyl compounds. Upon ozonolysis, each carbon atom of the double bond is converted into a carbonyl group, creating ketones or aldehydes depending on the substituents attached to the double bond. In the case of 1,2-dimethylcyclohexene, ozonolysis followed by reductive work-up (typically using a reducing agent like zinc in acetic acid) would lead to the formation of two ketones because the double bond is located at the 1,2-positions of a ring, and each carbon of the double bond is attached to a methyl group.
These ketones are acetone (due to the cleavage of the methylene group adjacent to the double bond) and a cyclic ketone (from the remaining part of the cyclohexene ring). The alkene moiety is cleaved, and the resulting ozonide intermediate is then reduced to form the final carbonyl products. This transformation is useful for understanding the position of double bonds in cyclic compounds through the identification of ketone products.