Question

58.5g of sodium iodide are dissolved in 0.5 dm³ . what concentration would this be?

Answer 1

`\huge{ \boxed{0.78 \: M}}`

Step-by-step explanation:

The concentration of the sodium iodide that's NaI can be found by using the formula:

`c = (m)/(M * v)`

where:

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

m is the mass in grams

M is the molar mass in g/mol

From the question:

m = 58.5 g

v = 0.5 dm³

Molar mass (M) of NaI = 149.894 g/mol

`\therefore \: c = \cfrac{58.5}{149.894 * 0.5} \\ = 0.78 \: M`