The equation of the line in standard form is 11y - 6x = 13. Therefore, the correct answer is B.
To find the equation of the line in standard form, we'll first determine the slope (m) using the coordinates (-4, -1) and (1.5, 2):
![\[ m = (y_2 - y_1)/(x_2 - x_1) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/vqy3fq0cgolowv3xchcub0teygxjk7luxm.png)
![\[ m = (2 - (-1))/(1.5 - (-4)) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kbkqrm4u46y4lixnp1f7xvllzs6e9ertbi.png)
![\[ m = (3)/(5.5) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9w0hxb3yqpohblcfxi2spfra1x9auro17h.png)
Now that we have the slope, we can use the point-slope form of a line
with either of the given points. Let's use (-4, -1):
![\[ (y - (-1)) = (3)/(5.5)(x - (-4)) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/t9ueiw01cn3cojnbftstkdk7bjf56i8u38.png)
![\[ y + 1 = (3)/(5.5)(x + 4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/5f2270585aujalwf7393li2uvl33s5m0ki.png)
Now, multiply both sides by 5.5 to clear the fraction:
5.5(y + 1) = 3(x + 4)
5.5y + 5.5 = 3x + 12
5.5y - 3x = 6.5
Finally, multiply both sides by 2 to get rid of the decimals:
11y - 6x = 13
So, the equation of the line in standard form is 11y - 6x = 13. Therefore, the correct answer is B.
The probable question may be:
What is the equation of this line in standard form? coordinates are= (-4,-1) and (1 1/2, 2)
A. 6x-7y=17
B.11x-6y=13
C.6x-11y=13
D.6x-11y=-13