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Lab scale tests performed on a cell broth with a viscosity of 5cP gave a specific cake resistance of 1 x1011 cm/g and a negligible medium resistance. The cake solids (dry basis) per volume of filtrate was 20 g/liter. It is desired to operate a larger rotary vacuum filter (diameter 8 m and length 12 m) at a vacuum pressure of 80 kPA with a cake formation time of 20 s and a cycle time of 60 s. Determine the filtration rate in volumes/hr expected for the rotary vacuum filter.

1 Answer

7 votes

Answer:

5.118 m^3/hr

Step-by-step explanation:

Given data:

viscosity of cell broth = 5cP

cake resistance = 1*1011 cm/g

dry basis per volume of filtrate = 20 g/liter

Diameter = 8m , Length = 12m

vacuum pressure = 80 kpa

cake formation time = 20 s

cycle time = 60 s

Determine the filtration rate in volumes/hr expected fir the rotary vacuum filter

attached below is a detailed solution of the question

Hence The filtration rate in volumes/hr expected for the rotary vacuum filter

V' = (
(60)/(20) ) * 1706.0670

= 5118.201 liters ≈ 5.118 m^3/hr

Lab scale tests performed on a cell broth with a viscosity of 5cP gave a specific-example-1
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