Question

You are conducting a calorimetry experiment using a calorimeter with 500 mL of water in its outer chamber to determine the enthalpy of reaction of a chemical reaction. The initial temperature of the water was 25 °C. After the reaction, the temperature of the water was 57.4 °C. Disregarding any heat loss to the walls of the container, calculate the Hf). (The specific heat of the water is 4.18 J/ (g*K)

Answer 1

Step-by-step explanation:

ΔH = q / n

q = m * c * ΔT

m - 500ml

c - 4.18 J/(g*K)

(ΔT) - 57.4 °C - 25 °C = 32.4 °C

q = (500 g) * (4.18 J/(g*K)) * (32.4 °C)

q ≈ 67,116 J

ΔH ≈ 67,116 J